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شائع علم المثلثات >

sin(x)sec(x)=2tan(x)-1

الحلّ

sin (x) sec (x) = 2 tan (x) - 1

الحلّ

x = \frac{π}{4} + πn

+1

درجات

x = 4 5^{\circ} + 18 0^{\circ} n

خطوات الحلّ

sin (x) sec (x) = 2 tan (x) - 1

من الطرفين

2 tan (x) - 1

اطرح

sin (x) sec (x) - 2 tan (x) + 1 = 0

Rewrite using trig identities

1 - 2 tan (x) + sec (x) sin (x)

sec (x) sin (x) = tan (x)

sec (x) sin (x)

sin, cos :

عبّر بواسطة

sec (x) sin (x)

sec (x) = \frac{1}{cos ( x )}

:Use the basic trigonometric identity

= \frac{1}{cos ( x )} sin (x)

\frac{1}{cos ( x )} sin (x)

بسّط:

\frac{sin ( x )}{cos ( x )}

\frac{1}{cos ( x )} sin (x)

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{1 sin ( x )}{cos ( x )}

1 \cdot sin (x) = sin (x) :

اضرب

= \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )}

= \frac{sin ( x )}{cos ( x )}

\frac{sin ( x )}{cos ( x )} = tan (x)

:Use the basic trigonometric identity

= tan (x)

= 1 - 2 tan (x) + tan (x)

بسّط

= 1 - tan (x)

1 - tan (x) = 0

انقل

1

إلى الجانب الأيمن

1 - tan (x) = 0

من الطرفين

1

اطرح

1 - tan (x) - 1 = 0 - 1

بسّط

- tan (x) = - 1

- tan (x) = - 1

- 1

اقسم الطرفين على

- tan (x) = - 1

- 1

اقسم الطرفين على

\frac{- tan ( x )}{- 1} = \frac{- 1}{- 1}

بسّط

tan (x) = 1

tan (x) = 1

tan (x) = 1 :

حلول عامّة لـ

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

رسم

أمثلة شائعة

sin(x)=sin(x+30)

sin (x) = sin (x + 3 0^{\circ})

cos^2(x)+7/12 cos(x)+1/12 =0

cos^{2} (x) + \frac{7}{12} cos (x) + \frac{1}{12} = 0

sec^{22}(x)=1-tan^2(x)

sec^{22} (x) = 1 - tan^{2} (x)

2sec(x)=1+cos(x)

2 sec (x) = 1 + cos (x)

sin^2(x)+cos(x)-cos^2(x)=0

sin^{2} (x) + cos (x) - cos^{2} (x) = 0