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inverse of laplace ((x^3+9))/(x^2+3x+2)

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(3x−2)−(x−3)²+11=0

Solution

x=0, x=9

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Solve by:

حلّ بالاستعانة بالصيغة التربيعيّة

حلّ بالاستعانة بالإكمال لمربّع

حلّ بالاستعانة بالتحليل إلى عوامل

One step at a time

(3x−2)−(x−3)²+11=0

(3x−2)−(x−3)²+11 وسّع: −x²+9x

−x²+9x=0

حلّ بالاستعانة بالصيغة التربيعيّة

x_{1, 2}=−9± √9²−4(−1)· 02(−1)

√9²−4(−1)· 0=9

x_{1, 2}=−9± 92(−1)

Separate the solutions

x₁=−9+92(−1) , x₂=−9−92(−1)

x=−9+92(−1) : 0

x=−9−92(−1) : 9

حلول المعادلة التربيعيّة هي

x=0, x=9

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أهلاً, اطرح سؤالا حول next term a_n=3n+2 أو اختر من الخيارات أدناه

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of laplace ((x^3+9))/(x^2+3x+2)

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