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periodicity of sin(3x)

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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∫ 5x²−8x−13x²−5 dx

Solution

5x−6√5 ln|x√5 +1|+6√5 ln|x√5 −1|−4ln|x²−5|+C

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∫ 5x²−8x−13x²−5 dx

5x²−8x−13x²−5 وسٌع: 5x²x²−5 −8xx²−5 −13x²−5

∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx :فعّل الميزة الخطيّة

=∫ 5x²x²−5 dx−∫ 8xx²−5 dx−∫ 13x²−5 dx

∫ 5x²x²−5 dx=−5√52 ln|x√5 +1|+5√52 ln|x√5 −1|+5x

∫ 8xx²−5 dx=4ln|x²−5|

∫ 13x²−5 dx=−132√5 (ln|x√5 +1|−ln|x√5 −1|)

=−5√52 ln|x√5 +1|+5√52 ln|x√5 −1|+5x−4ln|x²−5|−(−132√5 (ln|x√5 +1|−ln|x√5 −1|))

−5√52 ln|x√5 +1|+5√52 ln|x√5 −1|+5x−4ln|x²−5|−(−132√5 (ln|x√5 +1|−ln|x√5 −1|)) بسّط: 5x−6√5 ln|x√5 +1|+6√5 ln|x√5 −1|−4ln|x²−5|

=5x−6√5 ln|x√5 +1|+6√5 ln|x√5 −1|−4ln|x²−5|

أضف ثابت التكامل للحل

=5x−6√5 ln|x√5 +1|+6√5 ln|x√5 −1|−4ln|x²−5|+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

periodicity of sin(3x)

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