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domain of -((x+3)^2)/(20)+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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range 1x² +1x

Solution

−14 ≤ f(x)<0 or f(x)>0

Interval Notation

[−14 , 0)∪(0, ∞ )

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Solution steps

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ddx (4x(4x−2)(x²−3))

Take the constant out: (a·f)′=a·f ′

=4ddx (x(4x−2)(x²−3))

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=x, g=(4x−2)(x²−3)

=4(dxdx (4x−2)(x²−3)+ddx ((4x−2)(x²−3))x)

dxdx =1

ddx ((4x−2)(x²−3))=12x²−4x−12

=4(1· (4x−2)(x²−3)+(12x²−4x−12)x)

Simplify 4(1· (4x−2)(x²−3)+(12x²−4x−12)x): 4(16x³−6x²−24x+6)

=4(16x³−6x²−24x+6)

Solve instead

domain 1x² +1x

inverse 1x² +1x

intercepts 1x² +1x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of -((x+3)^2)/(20)+1

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