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foci y=x^2+64

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foci y=x²+64

Solution

(0, 2574 )

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Parabola Focus

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (the directrix)

Parabola standard equation

4p(y−k)=(x−h)² is the standard equation for an up-down facing parabola with vertex at (h, k),
and a focal length |p|

Rewrite y=x²+64 in the standard form: 4· 14 (y−64)=(x−0)²

(h, k)=(0, 64), p=14

Parabola is symmetric around the y-axis and so the focus lies a distance p from the center (0, 64) along the y-axis

(0, 64+p)

=(0, 64+14 )

Refine

(0, 2574 )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

foci y=x^2+64

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