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vertices −(x+3)220+1
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Solution
عظمى(−3,1)
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Solve by:
Find vertex using averaging the zeros
Find vertex using averaging the zeros
Find vertex using polynomial form
Find vertex using parabola form
Find vertex using vertex form
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y=−(x+3)220+1
Parabola equation in factored form
The vertex of an up-down facing parabola of the form y=a(x−m)(x−n)is the average of the zeros xv=m+n2
y=−(x+3)220+1
The parabola parameters are:
a=−120,m=2√5−3,n=−2√5−3
xv=m+n2
xv=(2√5−3)+(−2√5−3)2
(2√5−3)+(−2√5−3)2بسّط:−3
xv=−3
Plug in xv=−3to find the yvvalue
yv=1
لذلك رأس القطع المكافئ هو
(−3,1)
إذًا الرأس هو نقطة عظمى a<0إذا تحقّق أنّ إذًا الرأس هو نقطة صغرى a>0إذا تحقّق أنّ a=−120