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vertices (x+5)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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integral x⁴cos²(x)

Solution

15 x⁵cos²(x)+1320 (−32x⁵cos(2x)+5(16x⁴sin(2x)−4(−8x³cos(2x)+3(4x²sin(2x)−2(−2xcos(2x)+sin(2x))))))+C

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∫ x⁴cos²(x)dx

فعّل التكامل بالتجزيء: 15 x⁵cos²(x)−∫ −15 x⁵sin(2x)dx

=15 x⁵cos²(x)−∫ −15 x⁵sin(2x)dx

∫ −15 x⁵sin(2x)dx=−1320 (−32x⁵cos(2x)+5(16x⁴sin(2x)−4(−8x³cos(2x)+3(4x²sin(2x)−2(−2xcos(2x)+sin(2x))))))

=15 x⁵cos²(x)−(−1320 (−32x⁵cos(2x)+5(16x⁴sin(2x)−4(−8x³cos(2x)+3(4x²sin(2x)−2(−2xcos(2x)+sin(2x)))))))

بسّط

=15 x⁵cos²(x)+1320 (−32x⁵cos(2x)+5(16x⁴sin(2x)−4(−8x³cos(2x)+3(4x²sin(2x)−2(−2xcos(2x)+sin(2x))))))

أضف ثابت التكامل للحل

=15 x⁵cos²(x)+1320 (−32x⁵cos(2x)+5(16x⁴sin(2x)−4(−8x³cos(2x)+3(4x²sin(2x)−2(−2xcos(2x)+sin(2x))))))+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices (x+5)^2

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