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inverse of laplace (26)/((x-1)(x^2+25))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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taylor csc(x)

Solution

csc(1)−cot(1)csc(1)(x−1)+−csc(1)+2csc³(1)2 (x−1)²+cot(1)csc(1)−6csc³(1)cot(1)6 (x−1)³+csc(1)−2csc³(1)−6(−3csc³(1)cot²(1)−csc⁵(1))24 (x−1)⁴+…

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Taylor Series

Taylor series of function f(x) at a is defined as:
f(x)=f(a)+f^′(a)1! (x−a)+f^′′(a)2! (x−a)²+f^′′′(a)3! (x−a)³+…

Apply the Taylor Formula

=csc(1)+ddx (csc(x))(1)1! (x−1)+d²dx² (csc(x))(1)2! (x−1)²+d³dx³ (csc(x))(1)3! (x−1)³+…

Evaluate Derivatives

=csc(1)+−cot(1)csc(1)1! (x−1)+−csc(1)+2csc³(1)2! (x−1)²+cot(1)csc(1)−6csc³(1)cot(1)3! (x−1)³+csc(1)−2csc³(1)−6(−3csc³(1)cot²(1)−csc⁵(1))4! (x−1)⁴+…

بسّط

=csc(1)−cot(1)csc(1)(x−1)+−csc(1)+2csc³(1)2 (x−1)²+cot(1)csc(1)−6csc³(1)cot(1)6 (x−1)³+csc(1)−2csc³(1)−6(−3csc³(1)cot²(1)−csc⁵(1))24 (x−1)⁴+…

Partial Fractions Integration Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of laplace (26)/((x-1)(x^2+25))

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