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axis y=(x+5)^2

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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diameter x²−6x+8y+y²=0

Solution

d=10

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Circle Diameter

For a circle with radius r the diameter is defined as: d=2r

d=2r

جد نصف القطر

Radius given x²−6x+8y+y²=0: r=5

d=2· 5

بسّط

d=10

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أهلاً, اطرح سؤالا حول vertices (x+5)² أو اختر من الخيارات أدناه

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

axis y=(x+5)^2

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