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range of 2sqrt(4x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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f(x)=x¹¹x⁻³

Solution

Domain: x<0 or x>0

Range: f(x)>0

Intercepts: لا يوجد

Asymptotes: لا يوجد

Extreme Points: لا يوجد

Interval Notation

Domain: (−∞ , 0)∪(0, ∞ )

Range: (0, ∞ )

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Solution steps

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y=x²+1

Parabola standard equation

4p(y−k)=(x−h)² is the standard equation for an up-down facing parabola with vertex at (h, k),
and a focal length |p|

Rewrite y=x²+1 in the standard form: 4· 14 (y−1)=(x−0)²

Therefore parabola properties are:

(h, k)=(0, 1), p=14

Parabola is of the form 4p(y−k)=(x−h)² and is symmetric around the y-axis
Axis of symmetry is a line parallel to the y-axis which intersects the vertex:

x=0

Solve instead

ddx (x¹¹x⁻³ )

inverse x¹¹x⁻³

parity x¹¹x⁻³

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

range of 2sqrt(4x)

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