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horizontal tangent of 5x^2-2x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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horizontal tangent 5x²−2x

Solution

y=−15

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Horizontal tangent definition

The horizontal tangent shows where the function has a slope of zero.

Critical Points of 5x²−2x: x=15

Plug into function to get y-values:: (15 , −15 )

(15 , −15 )

Therefore, the horizontal tangent is:

y=−15

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domain 5x²−2x

range 5x²−2x

vertices 5x²−2x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

horizontal tangent of 5x^2-2x

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