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laplace y^{\prime}+2y=12sin(2t),y(0)=5

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laplace transform y^′+2y=12sin(2t), y(0)=5

Solution

y=−3cos(2t)+3sin(2t)+8e^−2t

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y′ +2y=12sin(2t)

Solve using Laplace transform: y=−3cos(2t)+3sin(2t)+8e^−2t

y=−3cos(2t)+3sin(2t)+8e^−2t

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

laplace y^{\prime}+2y=12sin(2t),y(0)=5

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