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inverse of x^2+(y+3)^2=16

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x²+(y+3)²=16

Solution

(a, b)=(0, −3), r=4

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x²+(y+3)²=16

Circle Equation

(x−a)²+(y−b)²=r² is the circle equation with a radius r, centered at (a, b)

Rewrite x²+(y+3)²=16 in the form of the standard circle equation

(x−0)²+(y−(−3))²=4²

Therefore the circle properties are:

(a, b)=(0, −3), r=4

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×▭▭	(	1	2	3	−	`x`
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inverse of x^2+(y+3)^2=16

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