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concavity y=(x^2+x+1)/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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perpendicular y=−5x+2, x=1

Solution

y=15 x−165

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x=1 ويمرّ عبر y=−5x+2 معامد على y=mx+b جد المستقيم

Find the perpendicular point: (1, −3)

y=−5x+2 احسب الميل في: m=−5

احسب ميل المعامد: m_p=15

(1, −3) الدي يمرّ عبر m=15 جد المستقيم صاحب الميل: y=15 x−165

y=15 x−165

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

concavity y=(x^2+x+1)/x

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