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range of 2cos(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx (6x−1 −3x+1 )

Solution

−3x²−18x−3(x−1)²(x+1)²

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ddx (6x−1 −3x+1 )

(f±g)′=f ′±g′ :استعمل قانون الجمع

=ddx (6x−1 )−ddx (3x+1 )

ddx (6x−1 )=−6(x−1)²

ddx (3x+1 )=−3(x+1)²

=−6(x−1)² −(−3(x+1)² )

−6(x−1)² −(−3(x+1)² ) بسّط: −3x²−18x−3(x−1)²(x+1)²

=−3x²−18x−3(x−1)²(x+1)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

range of 2cos(x)

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