diameter x^2-6x+8y+y^2=0

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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diameter x²−6x+8y+y²=0

Solution

d=10

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Circle Diameter

For a circle with radius r the diameter is defined as: d=2r

d=2r

Find the radius

Radius given x²−6x+8y+y²=0: r=5

d=2· 5

Refine

d=10

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
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diameter x^2-6x+8y+y^2=0

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