next term a_{n+1}=-3a_{n},a

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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y-intercept f(x)=(2x−2)³

Solution

(0, −8)

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(2x−2)³

y−تعريف نقاط التقاطع مع محور

x=0 هي نقطة يتحقّق فيها y−نقطة التقاطع مع محور

y=(2· 0−2)³ حلّ: y=−8

(0, −8)

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domain (2x−2)³

range (2x−2)³

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

next term a_{n+1}=-3a_{n},a_{1}=8

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